Equations Of Motion

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Equations Of Motion:

There are three basic equations of motion for bodies moving with uniform acceleration. These Equations are used to calculate the displacement (s), velocity(v), Time (t), and acceleration (a) of a moving body.

First Equation Of Motion

Suppose a body is moving with uniform acceleration “a” during some time interval “t”. Its initial velocity “vi” changes and is denoted as final velocity “vf”. If the body covers a distance “S” in this duration of time.

    In the First equation determine the final velocity of a uniformly accelerated body. Where,

    \(\vec{vi}\) = initial velocity

    \(\vec{vf}\)= final velocity

    \(\vec{a}\)= acceleration

     t = time

    The average acceleration is the change in velocity over a time interval

    acceleration = changes in velocity /time taken     

    \(\vec{a}\)=\(\frac{(\vec{v}_f – \vec{v}_i)}{t}\)

    \(\vec{a}\)t = \(\vec{vf}\)– \(\vec{vi}\)

    \(\vec{a}\)t + \(\vec{vi}\)= \(\vec{vf}\)

    \(\vec{vf}\)= \(\vec{vi}\)\(\vec{a}\)t

    Second Equation Of Motion:

    The second equation of motion determines the distance covered during some time interval “t”, while a body is accelerating from a known initial velocity.

    As we know, average velocity:

    \(v_{avg} = \frac{v_f + v_i}{2}\)

    \(v_{avg}=\frac{v_i + at + v_i}{2}\)

    \(v_{avg}= \frac{2v_i + at}{2}\)

    \(v_{avg}=\frac{2v_i}{2} + \frac{at}{2}\)

      \(v_{avg}=v_i + \frac{1}{2}at\)

    Velocity can be given as:

    \(v_{avg}=\frac{s}{t}\)

    \(\frac{s}{t}=v_i + \frac{1}{2}at\)

    \(S=(v_i + \frac{1}{2}at)t\)

    \(S = v_i t + \frac{1}{2}at^2\)

    Third Equation Of Motion:

    Third equation of motion determines the relationship among the velocity and the distance covered by a uniformly accelerated body, where the time interval is not mentioned.

    Let us take the first equation of motion.

    \(\vec{vf}\)= \(\vec{vi}\)\(\vec{a}\)t

    By squaring both sides of the equation we get:

    \(v_f^2 = (v_i + at)^2\)

    We know

    \( (a+b)^2 = a^2 + 2ab + b^2 \)

    \( v_f^2 = v_i^2 + 2v_iat + a^2t^2  \)

    \( v_f^2 = v_i^2 + 2a(v_i t + \frac{1}{2}at^2)   \)

    By second equation of motion

    \(S = v_i t + \frac{1}{2}at^2\)

    \( v_f^2 = v_i^2 + 2aS \)

    \( 2aS = v_f^2 – v_i^2 \)

    For the motion of bodies under the influence of gravity the equations of motion are slightly modified where distance is taken as (S=h) and acceleration is taken as g (a=g).

    Therefore the equation of motion is taken as.

    \(\vec{vf}\)= \(\vec{vi}\)\(\vec{a}\)t

    \(S = v_i t + \frac{1}{2}at^2\)

    \( 2aS = v_f^2 – v_i^2 \)

    Quiz

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